Math, asked by sultanaajmeri, 10 months ago

Simplify
a^2 (b – c) – b^2(c – a) – c^2(a - b)​

Answers

Answered by sanjeevravish321
1

Answer:hope it helps you mark me i needed brainlist answers

Step-by-step explanation:

a^2=b+c , b^2=c+a , c^2=a+b is given

Now we are asked to find the value of

1/1+a + 1/1+b + 1/1+c

So to solve this we need the value of 1+a , 1+b , 1+c and to find it what we will do is add a , b and c to the given equations……. okk let’s do it

a^2=b+c

a^2+a = a+b+c

a (a+1)=a+b+c

a+1= (a+b+c)/a

For 1+b also follow same process adding b on both sides and we get

1+b= (a+b+c)/ b

and for 1+c , adding c on both sides , we get

1+c=(a+b+c)/c

Now put these values in the question whose value is to be found

1/1+a + 1/1+b + 1/1+c

a/(a+b+c) + b/(a+b+c) + c/(a+b+c)

Taking LCM :

(a+b+c )/ (a+b+c ) =1

Answered by vishalkumar31702
1

Answer:

please give sufficient information about question like from which chapter this question is??

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