Question

simplify (a b + b c) square minus 2 a b square c​

Answer 1

$\huge\underline\textbf{Question}$

★ (ab+bc)²-2ab²c

$\huge\underline\textbf{Answer}$

→ (ab+bc)²-2ab²c

∞ So,here will use the identity (a+b)² = a²+b²+2ab

→ (ab)²+(bc)1+2(ab)(bc)-2ab²c

→ a²b²+b²c²+2ab²c-2ab²c

→ a²b²+b²c²

∞ As we know,negative digits can cancel with positive digits(in third step). So,we got the required answer.

$\huge\underline\textbf{Some\:Important\:Identities}$

★ (a+b)²=a²+b²+2ab)

★ (a-b)²=a²+b²-2ab

★ (a²-b²)=(a-b)(a+b)

★ (x+a)(x+b)=x²+(a+b)x+ab

Thank You!!

Answer 2

hope helps you make me as brainlist