Question

simplify:
( a + b + c)(a² + b² + c² - ab - bc - ca)

pls tell me the answer first I mark you as brainliest ​

Answer 1

Step-by-step explanation:

Multiply by 2 (both RHS and LHS)

Multiply by 2 (both RHS and LHS)2( a² + b² + c² - ab - bc - ca ) = 0

Multiply by 2 (both RHS and LHS)2( a² + b² + c² - ab - bc - ca ) = 0=> 2a² +2 b² + 2c² - 2ab - 2bc - 2ca = 0

Multiply by 2 (both RHS and LHS)2( a² + b² + c² - ab - bc - ca ) = 0=> 2a² +2 b² + 2c² - 2ab - 2bc - 2ca = 0=> a² + b² - 2ab + b² + c² - 2bc + a² + c² - 2 ca =0

Multiply by 2 (both RHS and LHS)2( a² + b² + c² - ab - bc - ca ) = 0=> 2a² +2 b² + 2c² - 2ab - 2bc - 2ca = 0=> a² + b² - 2ab + b² + c² - 2bc + a² + c² - 2 ca =0=> (a-b)² + (b-c)² + (c-a)² = 0

Multiply by 2 (both RHS and LHS)2( a² + b² + c² - ab - bc - ca ) = 0=> 2a² +2 b² + 2c² - 2ab - 2bc - 2ca = 0=> a² + b² - 2ab + b² + c² - 2bc + a² + c² - 2 ca =0=> (a-b)² + (b-c)² + (c-a)² = 0Now, sum of three positive numbers can not be zero there fore all the numbers are zero.

Multiply by 2 (both RHS and LHS)2( a² + b² + c² - ab - bc - ca ) = 0=> 2a² +2 b² + 2c² - 2ab - 2bc - 2ca = 0=> a² + b² - 2ab + b² + c² - 2bc + a² + c² - 2 ca =0=> (a-b)² + (b-c)² + (c-a)² = 0Now, sum of three positive numbers can not be zero there fore all the numbers are zero.=> a = b = c

mark me as brainlist

Answer 2

Answer:

a³ + b³ + c³ -3abc

Step-by-step explanation:

hope it helps