Question

simplify (a) (root5+root 2)^2??
(b) (root11-root7) (root11+root7)​

Answer 1

• (√5 + √2)²

If we carefully observe the given problem ; it is in the form of (a+b)² .

Here :

• a = √5
• b = √2

So following the same identity we will solve the given problem.

(a+b)² = a² + 2ab + b²

Substituting the values :

☞ (√5 + √2)² = (√5)² + 2 × √5 × √2 + (√2)²

☞ (√5 + √2)² = 5 + 2 × √10 + 2

☞ (√5 + √2)² = 5 + 2 + 2√10

☞ (√5 + √2)² = 7 + 2√10

• (√11 - √7)(√11 + √7)

If we observe carefully the given problem is in the form of identity : (a+b)(a-b) .

Here :

• a = √11
• b = √7

Following the same identity we will solve the given problem.

(a+b)(a-b) = a² - b²

Substituting the values :

☞ (√11 - √7)(√11 + √7) = (√11)² - (√7)²

☞ (√11 - √7)(√11 + √7) = 11 - 7

☞(√11 - √7)(√11 + √7) = 4

Note :

When a root is with power of 2 ; the power and root gets cancelled.

Answer 2

Answer:

hey :D

Step-by-step explanation: