Question

Simplify (ab+bc)²

– 2ab²c​

Answer 1

Answer:

(ab+bc)²– 2ab²c

= [ab² + 2(ab*bc) + bc²] - 2ab²c {Using the identity (a+b)² = a² + 2(ab) + b²}

= ab² + 2ab²c + bc² - 2ab²c

= ab² + bc²

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