Simplify (ab+bc)²
– 2ab²c
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Answer:
(ab+bc)²– 2ab²c
= [ab² + 2(ab*bc) + bc²] - 2ab²c {Using the identity (a+b)² = a² + 2(ab) + b²}
= ab² + 2ab²c + bc² - 2ab²c
= ab² + bc²
Hope it will help
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aarush07in:
best answer ever
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