Question

Simplify ab_[bc_{ca+ab+(bc_ca_ab)}]​​

Answer 1

:-ab-[bc-{ca+ab+(bc-ca-ab)}]

= ab-[bc-{ca+ab+bc-ca-ab]}

= ab-[bc-{bc}]

= ab-[bc-bc]

= ab.

In first step u Cut the ca+ab and ca-ab.

Then in second step no need to cut anyone.

Then in third step cut bc-bc.

Then u get the answer..

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