Math, asked by badrimadhusudhan66, 1 day ago

simplify AB''C+B+BD'+ABD'+A'C​

Answers

Answered by abenkr2013
2

Step-by-step explanation:

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Answered by Nehavemula
2

Answer:

Here we go ,

AB'C+ B(1+D')+ABD'+A'C

=> AB'C+ B+ABD'+A'C { as 1+X=1 }

=> AB'C+ B(1+AD')+A'C

=> AB'C+ B +A'C { as 1+X=1 }

=> AB'C+A'C+B

=> C(A' + AB')+B

=> C(A' + B') + B { as A'+AB'=A'+B' , distributive law}

=> CA'+CB'+B

=> CA'+C+B { as A+A’B=A+B , distributive law}

=> C+B { as A+AB'=A, absorption law}

Hence proved as LHS=RHS.

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