Math, asked by kavitapardhi364, 17 days ago

simplify and express each of the following in exponential form​

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Answered by fahimabrarcox162
0

(i)[(2)^3×(3)^4×(2)^2]/[3×(2)^5]

(2)^5×(3)^4/(3)×(2)^5

(3)^3=27

(ii) [(5^2)^3×(5)^4] ÷(5)^7

[(5)^6x(5)^4] ÷(5)^7

(5)^10÷(5)^7=(5)^3=125

(iii) (5^2)^4÷(5)^3=(5)^8÷(5)^3=(5)^5=3125

(iv) 3×(7)^2×(11)^8/3×7×(11)^3=7×{11)^5 (v) (3)^7/(3)^4×(3)^3=(3)^7×(3)^7=1

(vi) 1+1+1=3

(vii)1x1x1=1

(viii)(1+1)x1=2×1=2

(2)6=(2)^2xa^2=4a^2

(ix) (2)^8×(a)^5/(22)^3×(a)^3=(2)^8×(a)^2/

(x) (a^5/a^3)x(a)^8= (a)^13/(a)^3=a^10

(xi) (22)^5xa^8÷b^3/(22)^5xa^5÷b^2-a^3÷b

(xii) (2^3×2)^2=(8x2)^2=(16)^2=256

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Answered by muskangarg18714
0

Answer:

(i)(2)3×(3)4×(2)2/3×(2)5

(2)5×(3)4/(3)×(2)5

(3)3=27

(ii) [(52)3×(5)4]÷(5)7

[(5)6×(5)4]÷(5)7

(5)10÷(5)7=(5)3=125

(iii) (52)4÷(5)3=(5)8÷{5)3=(5)5=3125

(iv) 3×(7)2×(11)8/3×7×(11)3=7×{11)5

(v) (3)7/(3)4×(3)3=(3)7×(3)7=1

(vi) 1+1+1=3

(vii)1×1×1=1

(viii)(1+1)×1=2×1=2

(ix) (2)8×(a)5/(22)3×(a)3=(2)8×(a)2/(2)6=(2)2×a2=4a2

(x) (a5/a3)×(a)8= (a)13/(a)3=a10

(xi) (22)5×a8b3/(22)5×a5b2=a3b

(xii) (23×2)2=(8×2)2=(16)2=256

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