Question

$\large \bigstar \: \bf \pink{Question :-}$

Find the Area of Rectangle, If the Length is 5 cm & Breadth is 10 cm .​

Answer 1

Question :-

• Find the Area of Rectangle, If the Length is 5 cm & Breadth is 10 cm .

Answer :-

• Area of Rectangle is 50 cm² .

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Given :-

• Length of Rectangle = 5 cm
• Breadth of Rectangle = 10 cm

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To Find :-

• Area of Rectangle = ?

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Solution :-

• Here, Length is given 5 cm . Breadth is given 10 cm . And, we have to calculate the Area .

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➻ Formula Required :-

• $\sf{Area \: of \: Rectangle = L \times B}$

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➻ Where ,

• L denotes to the Length
• B denotes to the Breadth

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➻ By substituting the given values :-

$\dag \: \: \sf{ Area \: of \: Rectangle = Length \times Breadth}$

$\Longrightarrow \: \: \sf{Area \: of \: Rectangle \: = \: 5 \: \times \: 10}$

$\Longrightarrow \: \: \sf{Area \: of \: Rectangle \: = \: 50 \: {cm}^{2} }$

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Hence :-

• Area = 50 cm² .

$\rule{190pt}{3pt}$

$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \pmb {\sf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Square = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \sf{Area \: of \: Rectangle = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Triangle = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Parallelogram = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Trapezium = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf {Area \: of \: Rhombus = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}$

Answer 2

Given:-

• Length=5 cm
• Breadth=10 cm

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To find:-

Area of rectangle

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Formulae:-

$\text \pink{Length×Breadth}$

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Solution:-

Area of Rectangle= Length×Breadth

⟿ Area=5×10

⟿ Area=50 cm²

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Hence, Area of a Rectangle is 50 cm²

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More formulas to learn:

Perimeter of Square= 4×l or l+l+l+l

Perimeter of Rectangle=2(l+b)

Area of Square=l²

Area of rectangle=l×b

Area of triange=½ bh

Area of parallelogram=Base×Height