Question

Simplify and express the answer in exponential form.
9³ x a⁷ x 15² x 8⁰ x b⁵
----------------------------------
3⁴ x a⁵ x 5³ x b²​

Answer 1

Step-by-step explanation:

Given :-

Current drawn by filament of an electric bulb = 25 A

Time taken by the electric bulb = 10 m

To Find :-

The amount of electric charge that flows through the circuit.

Analysis :-

Here we are given with the current and time taken by the electric bulb.

In order to find the charge flown substitute the values given in the question such that charge flown is equal to current multiplied by the time.

Solution :-

We know that,

i = Current

q = Charge

t = Time

Using the formula,

\underline{\boxed{\sf Charge=Current \times Time}}

Charge=Current×Time

Given that,

Current (i) = 25 A

Time (t) = 10 min = 600 sec

Substituting their values,

⇒ q = i × t

⇒ q = 25 × 600

⇒ q = 15000 C

⇒ q = 1.5 × 10⁴

Therefore, the amount of electric charge that flows through the circuit is 1.5 × 10⁴.

Answer 2

Answer:

$\frac{ {9}^{3} \times {a}^{7} \times {15}^{2} \times {8}^{0} \times {b}^{5} }{ {3}^{4} \times {a}^{5} \times {5}^{3} \times {b}^{2} } \\ = \frac{ {3}^{6} \times {a}^{7} \times {3}^{2} \times {5}^{2} \times 1 \times {b}^{5} }{ {3}^{4} \times {a}^{5} \times {5}^{3} \times {b}^{2} } \\= \frac{ {3}^{8} \times {a}^{7} \times {5}^{2} \times {b}^{5} }{ {3}^{4} \times {a}^{5} \times {5}^{3} \times {b}^{2} } \\ = \frac{ {3}^{4} \times {a}^{2} \times {b}^{3} }{5} \\ = \frac{81 \times {a}^{2} \times {b}^{3} }{5}$

$\frac{81 \times {a}^{2} \times {b}^{3} }{5} \: is \: the \: right \: answer$

hope this will help you.