simplify and express the following in exponential form [(2/7)⁰]⁵
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any no. to the power 0 always gives 1 as it's ans
thus
(2/7)^0= 1
and 1 to the power any no. gives 1 thus
1^5 = 1
[(2/7)⁰]⁵ = (1)^5= 1
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