Question

Simplify and express the result in the form of a rational numbers​ .(3/11×9)+(-6/21÷1/-42)-(-4/3×9/24)-(-2/7×-21) please solve it. it is class 7 maths rational number chapter and I have try to solve many times but not got correct answer please help in this question.please don take only point give me please correct answer​

Answer 1

Given:-

• In attachment.

To find:-

• The result in rational form.

Solution:-

$\\ \\ \\ = >( \frac{3}{11} \times \frac{2}{9}) + ( \frac{( - 6)}{21} \div \frac{1}{( - 42)} - ( - 1 \times \frac{1}{3} \times \frac{9}{24}) \\ - ( \frac{( - 2)}{7} \times 21) \\ \\ \\ = > \binom{2}{11 \times 3} + ( \frac{ - 6}{21} \times ( - 42)) - ( \frac{ - 2}{3} \times \frac{9}{24} ) \\ - ( - 2 \times ( - 3)) \\ \\ \\ = > \binom{2}{33} + (12) + \binom{1}{4} - (6) \\ \\ \\ = > \binom{2}{33} + \binom{1}{4} + 6 \\ \\ \\ = > \binom{8 + 33 + 792}{132} \\ \\ \\ = > \binom{833}{132} \\ \\ \\ = > 6 \times \frac{41}{132}$$\small\bold\red{Required \: Answer↗⬆↖}$

Explanation:-

Hey mate! For your question above solution has been given.

In first step we simplified the first bracket.

Then we made sure of making each rational number given in standard form and then solving.

On solving we got 833/132 which was further changed in mixed as 6*41/132.

Additional information:-

What are rational numbers?

A rational number is any number that can be named in the form of a/b where a and b are integers and b is not equal to zero.

For Ex:-

• 5/6;6/11; (-13)/9;6/(-17), etc..

NOTE THAT:-

• every natural number is a rational number but a rational number need not be a natural number.

As:- 2 can be written as a rational number 2/1 but 7/8 cannot be written as a natural number.

hope it helped!

Answer 2

$= > 6 \times \frac{41}{52} is \: your \: required \: answer.$

hope it helped you buddy!