simplify and factorise (a +b + c )^2 - ( a _ b _ -c)^2 + 4 b^2 - 4 c^2.
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Answer:
4(b+c)(a+b-c)
Step-by-step explanation:
(a +b + c )^2 - ( a -b-c)^2 + 4 b^2 - 4 c^2
=(a+b+c+a-b-c)[(a+b+c-(a-b-c)]+ 4 b^2 - 4 c^2
=2a*(a+b+c-a+b+c)+ 4 b^2 - 4 c^2
=2a(2b+2c)+ 4 b^2 - 4 c^2
=4ab+4ac+ 4 b^2 - 4 c^2
=4a(b+c)+4(b+c)(b-c)
=4(b+c)(a+b-c)
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