Simplify and factorise in bracket a + b + C whole square minus in bracket a minus b minus C whole square + 4 b square - 4 c square
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Answer:
(a+b+c)2
= (a+b)2 + c2 + 2c(a+b) (a+b+c)2 =a2+b2+2ab+c2+2ac+2bc =a2+b2+c2+2ab+2ac+2bc
(a - b - c)²
= (a - b - c)(a - b - c)
= a(a - b - c) - b(a - b - c) - c(a - b - c)
= a² - ab - ac - ab + b² + bc - ac + bc +
c²
= a² + b² + c² - 2ab - 2ac + 2bc
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plz refer to the above attachment for the answer
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