Question

Simplify and find the value of
(a) (729)1/6
(b) (64)2/3
(c) (243)6/5​

Answer 1

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Answer 2

(a.) Therefore the value of $729^1^/^6$ is '3'.

( b.) Therefore the value of $64^2^/^3$ is '16'.

( c.) Therefore the value of $243^6^/^5$ is '729'.

Given:

The numbers: 729, 64, 243

To Find:

The value of:

(a.) $729^1^/^6$

(b.) $64^2^/^3$

(c.)$243^6^/^5$

Solution:

The given question can be solved as shown below.

(a.) $729^1^/^6$

729 = 3⁶

⇒ $729^1^/^6$ = $( 3^6 ) ^1^/^6$ = 3

Therefore the value of $729^1^/^6$ is '3'.

(b.) $64^2^/^3$

64 = 2⁶

⇒ $64^2^/^3$ = $( 2^6 ) ^2^/^3$ = $( 2^2)^2$ = 2⁴ = 16

Therefore the value of $64^2^/^3$ is '16'.

(c.)$243^6^/^5$

243 = 3⁵

⇒ $243^6^/^5$ = $(3^5)^6^/^5$ = 3⁶ = 9 × 9 × 9 = 729

Therefore the value of $243^6^/^5$ is '729'.

(a.) Therefore the value of $729^1^/^6$ is '3'.

( b.) Therefore the value of $64^2^/^3$ is '16'.

( c.) Therefore the value of $243^6^/^5$ is '729'.

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