Question

simplify boolean expression x'(x+y)+z'+xy

Answer 1

X'(X+Y)+Z'+ XY

• using distributive law X(Y+Z) = XY + XZ

X'X + X'Y + Z'+ XY

• using commutative law XY = YX

XX' + X'Y + Z'+ XY

• using complimentary law XX' = 0

0 + X'Y + Z'+ XY

X'Y + Z' + XY

• taking Y common

Y ( X' + X ) + Z'

• using complimentary law X+X' = 1

Y×1 + Z'

Y + Z'

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