Math, asked by hitdevnb, 1 year ago

Simplify by rationalizing the denominator √5-√2/√5+√2-√5+√2/√5-√2

Himanshu1629: plz specify your question......as i can't see any denominator in the above question

Himanshu1629: sorry got ya

Answers

Answered by abdul143

√5-√2/√5+√2-√5+√2/√5-√2.
[√5-√2/√5+√2×√5-√2/√5-√2]-[√5+√2/√5-√2×√5+√2/√5+√2].
7+1√10/5-7-1√10/5=7+1√10-7-1√10/5=√10/5

hitdevnb: Can u explain in detail

Himanshu1629: brother u can simply replace √10with it's value......and get the answer

hitdevnb: Yes

hitdevnb: Thanks a lot!!

Answered by Himanshu1629

here for convenience i am separating both the particular terms in individual brackets

[√5-√2/√5+√2] - [√5+√2/√5-√2]
now rationalizing both terms within their brackets
we get,
{ [(√5-√2/√5+√2) × (√5-√2/√5-√2)] - [(√5+√2/√5-√2) × (√5-√2/√5-√2)] }
= [ (√5-√2)²/ (5-2)] - [(5-2)/(√5-√2)²]
= [ (5+2-2√5√2)/3] - [ 3/(5+2-2√5√2) ]
= [ (7-2√10)/3] - [ 3/(7-2√10) ]
= [ 3.5 - 0.67(3.16/3)] - [ 0.42 - 1.5(3/3.16)]
= [ 3.5 - 0.67(1.05)] - [0.42 - 1.5 (0.94)]
= [ 3.5 - 0.7035] - [ 0.42 - 1.41]
= [ 2.7965] - [-0.99]
= 2.7965 + 0.99
= 3.7865

Himanshu1629: hope it helped

Himanshu1629: if it really did....thn plz mark the brainliest tag

Previous Question

Next Question