Simplify by using identities:-x6 - y6
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x6 – y6 = (x2)3 – (y2)3 = (x2 – y2)[(x2)2 + x2y2 +(y2)2], by (3)
= (x + y)(x – y)(x4 + x2y2 + y4),
Mathematics11:
Which identity you has used in x6 - y6
factorization
I have asked identity 1,2,3,4,5,6,7
3,1
ok thanks
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◆Ekansh Nimbalkar◆
hello friend here is your required answer
hello friend here is your required answer
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Thank you. Which class do you belong ?
class 9th
please answer my another question that is Factorise by using Factorisation x3 + 2x2 + 1x- 12
please answer my another question that is Factorise by using Factorisation x3 + 2x2 + 1x- 12
please answer my another question that is Factorise by using Factorisation x3 + 2x2 + 1x- 12
please answer my another question that is Factorise by using Factorisation x3 + 2x2 + 1x- 12.
x3+2x2+1x-12=x×3+2x×2+1x-12=3x+4x+x-12=(3+4+1)x-12=8x-12
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