Question

Simplify

E = a3/2 cosec2 (tan-1 a/ß) + ß3/2 sec2 (tan-1 a/ß) when a, ß > 0.

Answer 1

Answer:

Hope it will help you

Step-by-step explanation:

Let tan-1 a/ß = θ ⇒ tan θ = a/ß

Now we have E = (a^3cosec^2 θ + ß^3 sec^2 θ)/2

or, E = (a^3cos^2 θ + ß^3sin^2 θ )/(2sin^2 θ cos^2 θ ) …… (1)

Now, sin θ = a/√(a^2 + ß^2) and cos θ = ß/√(a^2+ß^2)

Putting values of sin θ and cos θ in (1)

E = (a + ß) (a² + ß²)/ 2.

Answer 2

Answer:

jkw disbanding theta theta thetea

Step-by-step explanation:

hence proved