Question

simplify
fast please please please
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Answer 1

$\dashrightarrow 2^2\times \dfrac{3^2}{2^{-2}}\times 3^{-1}$

$\dashrightarrow \dfrac{2^2}{2^{-2}}\times 3^2\times 3^{-1}$

We know that exponents (powers or index) with same bases gets subtracted on division, and added on Multiplication.

In other words,

$\bullet\quad\rm a^m \div a^n = a^{m-n}$

And

$\bullet\quad\rm a^m \times a^n = a^{m+n}$

Hence,

$\dashrightarrow 2^{2-(-2)}\times 3^{2+(-1)}$

$\dashrightarrow 2^{2+2}\times 3^{2-1}$

$\dashrightarrow 2^{4}\times 3^{1}$

$\dashrightarrow 16\times 3$

$\bf\dashrightarrow 48$