Question

solve by factorisation. 2x^square+9x+9=0​

Answer 1

Answer:

$2 {x}^{2} + 9x + 9 = 0 \\ \\ = > 2 {x}^{2} + (6 + 3)x + 9 = 0 \\ \\ = > 2 {x}^{2} + 6x + 3x + 9 = 0 \\ \\ = > 2x(x + 3) + 3(x + 3) = 0 \\ \\ = > (2x + 3)(x + 3) = 0 \\ \\ either \: 2x + 3 = 0 \\ \\ = > 2x = - 3 \\ \\ = > x = \frac{ - 3}{2} \\ \\ or \: x + 3 = 0 \\ \\ = > x = - 3$

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Answer 2

Step-by-step explanation:

sum = 9

product = 18

2x^2 + 3x + 6x + 9 = 0

x*(2x+3) +3(2x +3) = 0

(x+3)*(2x+3) = 0

x+3 = 0 ; 2x + 3 = 0

x = -3 ; -3/2