Math, asked by Anonymous, 10 months ago

Simplify it. ...........​

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Answered by Anonymous
9

Heya!

Here is ur answer..

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(i)3√45-√125+√200-√50

= 3(√9)(√5)- (√25)(√5)+(√2)(√100)-(√2)(√25)

= 3(3)(√5)-(5)(√5)+(√2)(10)-(√2)(5)

= 9√5-5√5+10√2-5√2

= 4√5 + 5√2

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(ii) \frac{2 \sqrt{30} }{ \sqrt{6} }  -  \frac{3 \sqrt{140} }{ \sqrt{28} }  +  \frac{ \sqrt{55} }{ \sqrt{99} }  \\  \\  =   \frac{2 \sqrt{6}  \times  \sqrt{5} }{  \sqrt{6}  }  -  \frac{6 \sqrt{7} \times  \sqrt{5}  }{2 \sqrt{7} }  +  \frac{ \sqrt{11} \times  \sqrt{5}  }{ 3\sqrt{11} }  \\  \\  = 2 \sqrt{5 }  - 3 \sqrt{5 }  +   \frac{ \sqrt{5} }{3}  \\  \\  =  \frac{6 \sqrt{5}  - 9 \sqrt{5}  +  \sqrt{5} }{3}  \\  \\  =  \frac{-2 \sqrt{5} }{3}

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(iii) √72 +√800 -√8

= (√2)(√36) + (√2)(√400)-(√2)(√4)

= √2(6) + √2(20) -√2(2)

= 6√2 + 20√2 -2√2

= 26√2 -2√2

= 24√2

Hope it helps u..


Anonymous: Wlcum bruh
Anonymous: :)
Answered by Anonymous
3

Answer

(i)3√45-√125+√200-√50

= 3(√9)(√5)- (√25)(√5)+(√2)(√100)-(√2)(√25)

= 3(3)(√5)-(5)(√5)+(√2)(10)-(√2)(5)

= 9√5-5√5+10√2-5√2

= 4√5 2

(iii) √72 +√800 -√8

= (√2)(√36) + (√2)(√400)-(√2)(√4)

= √2(6) + √2(20) -√2(2)

= 6√2 + 20√2 -2√2

= 26√2 -2√2

= 24√2

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