Question

simplify log36 interms of log 2 and log 3

Answer 1

log 36
= log (2×2×3×3)
= log (2²×3²)

[Now, log ab = log a + log b]

= log (2²) + (log 3²)

[Now, log aⁿ = n log a ]

= 2 log 2 + 2 log 3
= 2( log 2 + log 3)

Answer 2

Hey there!
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36
=2*18
=2*2*9
=2*2*3*3

log 36 =log(2²*3²)

logab=loga+logb

log36=log2²+log3²

logm^n=nlogm

finally,

log36= 2 log 2 + 2 log 3

= 2( log 2+log3)
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hope helped!