Question

Simplify
No Wrong answer plz​

Answer 1

$\frac{(81)^{n}3 ^{5} - (3) ^{4n - 1}(243) }{ {(9)}^{2n} {(3)}^{3} }$

$\frac{(3)^{ 4n}3 ^{5} - {(3)}^{4n - 1} (3)^{5} }{ {(3)}^{2(2n)}(3) ^{3} }$

$\frac{3^{4n + 5} - {3}^{4n - 1 + 5} }{ {3}^{4n + 3} }$

${3}^{4n + 5} - {3}^{4n - 4} = {3}^{4n + 3}$

${3}^{4n + 5} = {3}^{4n + 3} + 3^{4n - 4}$

$4n + 5 = 4n + 3 + 4n - 4$

$4n - 8n = 3 - 4 - 5$

$- 4n = - 6$

$n = \frac{6}{4} = 1 \frac{1}{2}$

Answer 2

Refer the attachment for complete answer ✔️