Math, asked by muskansethi, 1 year ago

simplify (question is given above in the picture)

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Answered by rakeshmohata
0
Hope u like my process
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 {( \frac{ {x}^{b} }{ {x}^{c} }) }^{b + c - a}  \times  {( \frac{ {x}^{c} }{ {x}^{a} } )}^{c + a - b}  \times  {( \frac{ {x}^{a} }{ {x}^{b} }) }^{a + b - c}  \\  =  {( {x}^{(b - c)}) }^{b + c - a}  \times  { ({x}^{(c - a)} )}^{c + a - b}  \times  {( {x}^{(a - b)}) }^{a + b - c}  \\  =  {x}^{(b - c)(b + c - a)}  \times  {x}^{(c - a)(c + a - b)}  \times  {x}^{(a  -  b)(a + b - c)}  \\  =  {x}^{ {b}^{2} -  {c }^{2}  - ab + ac }  \times  {x}^{ {c}^{2}  -  {a}^{2}  - b c + ab}  \times  {x}^{ {a}^{2} -  {b}^{2} -ac  + bc  }  \\  =  {x}^{ {b}^{2} -  {c}^{2}   - ab + ac +  {c}^{2} -  {a}^{2}  - bc + ab +  {a}^{2} -  {b}^{2}   - ac + bc }  \\  =  {x}^{0}  = 1
Hope this is ur required answer
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