Question

Simplify root. 162+root
108 by root72 +root 48

Answer 1

3/2 is the correct answer

I HOPE YOU UNDERSTAND

Answer 2

$\frac{\sqrt{162}+\sqrt{108}}{\sqrt{72}+\sqrt{48}}=\frac{3}{2}$

Step-by-step explanation:

Given : Expression $\frac{\sqrt{162}+\sqrt{108}}{\sqrt{72}+\sqrt{48}}$

To find : Simplify the expression ?

Solution :

We factories the number and simplify them,

$\frac{\sqrt{162}+\sqrt{108}}{\sqrt{72}+\sqrt{48}}=\frac{\sqrt{9\times 9\times 2}+\sqrt{6\times 6\times 3}}{\sqrt{6\times 6\times 2}+\sqrt{4\times 4\times 3}}$

$\frac{\sqrt{162}+\sqrt{108}}{\sqrt{72}+\sqrt{48}}=\frac{9\sqrt{2}+6\sqrt{3}}{6\sqrt{2}+4\sqrt{3}}$

Taking common term out,

$\frac{\sqrt{162}+\sqrt{108}}{\sqrt{72}+\sqrt{48}}=\frac{3(3\sqrt{2}+2\sqrt{3})}{2(3\sqrt{2}+2\sqrt{3})}$

$\frac{\sqrt{162}+\sqrt{108}}{\sqrt{72}+\sqrt{48}}=\frac{3}{2}$

Therefore, $\frac{\sqrt{162}+\sqrt{108}}{\sqrt{72}+\sqrt{48}}=\frac{3}{2}$

#Learn more

Simplify : root 50 - root 98 +root 162

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