Question

simplify: (sec2Q-1)(1-cosec2Q)

Answer 1

Step-by-step explanation:

if the answer is right please mark it as BRAINLIEST

Answer 2

ANSWER

$( {sec}^{2} \alpha - 1)( {cosec}^{2} \alpha - 1) \\ \\ ( \frac{1}{ {cos}^{2} \alpha } - 1)( \frac{1}{ {sin}^{2} \alpha } - 1 ) \\ \\ ( \frac{1 - {cos}^{2} \alpha }{ {cos}^{2} \alpha } )( \frac{1 - {sin}^{2} \alpha }{ {sin}^{2} \alpha } ) \\ \\ \frac{ {sin}^{2} \alpha }{ {cos}^{2} \alpha } \times \frac{ {cos}^{2} \alpha }{ {sin}^{2} \alpha } \\ \\ = 1$

FORMULA USED....

$1 - {sin}^{2} \alpha = {cos}^{2} \alpha \\ \\ 1 - { \cos }^{2} \alpha = { \sin }^{2} \alpha$

ANSWER BY...

PURPLE WORLD

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