Question

Simplify secA (1 − sinA) (secA + tanA)

Answer 1

Hi ,

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We know that ,

i ) secA = 1/cosA

ii ) sinA/cosA = tanA

iii ) sec²A - tan²A = 1

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secA( 1 - sinA )( secA + tanA )

= ( secA - secAsinA )( secA + tanA )

= ( secA - sinA/cosA )( secA + tanA )

= ( secA - tanA )( secA + tanA )

= ( sec²A - tan²A )

= 1

I hope this helps you.

: )

Answer 2

Step-by-step explanation:

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