Math, asked by samir567, 1 year ago

simplify simplify simplify​

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Answered by sagarmankoti
1

 \:  \:  \:  \:   \sqrt{18 {m}^{3} {n}^{ - 1}  } \:    \div  \:  \sqrt{2 {m}^{ - 1}n  } \\  =  \sqrt  {   \frac{18 {m}^{3} {n}^{ - 1}}{2 {m}^{ - 1}n }}  \\  =  \sqrt{ \frac{18 {m}^{3} \times m }{2n \times n} }  \\  =  \sqrt{ \frac{9 {m}^{4} }{ {n}^{2} } }  \\  =  \frac{3 {m}^{2} }{n}

Answered by Anonymous
2

hope it helps!

#sumedhian ❤❤

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