Question

Simplify sin square theta + cos square theta and write your answer.

Answer 1

Step-by-step explanation:

answer is in picture ......

Answer 2

$\sin^2 \theta$ + $\cos^2 \theta$ = 1

Step-by-step explanation:

We have,

$\sin^2 \theta$ + $\cos^2 \theta$

To find, $\sin^2 \theta$ + $\cos^2 \theta$ = ?

We know that,

$\sin \theta$ = $\dfrac{p}{h}$ and $\cos \theta$ = $\dfrac{b}{h}$

Where, p = perpendicular, b = base and h = hypotaneous

∴ $\sin^2 \theta$ + $\cos^2 \theta$

= $(\dfrac{p}{h})^2+(\dfrac{b}{h})^2$

= $\dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}$

= $\dfrac{p^2+b^2}{h^2}$

By Pythagoras Theorem,

$h^2$ = $p^2$ + $b^2$

= $\dfrac{h^2}{h^2}$

= 1

∴ $\sin^2 \theta$ + $\cos^2 \theta$ = 1