simplify: (sin³A+cos³A/ Sin A+cosA) + sinAcosA
plz answer fast. I don't have time
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Step-by-step explanation:
sin³A+cos³A
=(sinA+cosA)(sin²A+cos²A-sinAcosA)
sin³A+cos³A/(sinA+cosA) + sinAcosA
=sin²A+cos²A-sinAcosA +sinAcosA
=1-sinAcisA+sinAcosA
=1
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