Math, asked by akashkapare, 8 months ago

simplify sinx+sin3x/cosx+cos3x​

Answers

Answered by himanshusingh52
0

Answer:

sin 3x = 3 sin x - 4 sin3 x

sin 5x = 5 sin x - 20 sin3 x + 16 sin5 x

cos 3x = -3 cos x + 4 cos3 x

cos 5x = 5 cos x - 20 cos3 x + 16 cos5 x

Substitute, combine, and reduce.

Answered by rm7645484
5

Answer:

tan2x

Step-by-step explanation:

we have,,

(since+sin3x)/(cosx+cos3x)

so, (sinx+3sinx-4sin³x)/(cosx+4cos³x-3cosx)

= (4sinx-4sin³x)/(4cos³x-2cosx)

= 4sinx(1-sin²x)/2cosx(2cos²x-1)

= 2tanx(cos²x)/(2cos²x-1)

= 2tanx(cos²x)/cos2x

= 2sinxcosx/cos2x

= sin2x/cos2x

= tan2x ....ans.

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