Question

Simplify step by step

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Answer 1

Answer:

$( { \:{2}^{ - 1} + {4}^{ - 1} + {3}^{ - 1}})^{ - 1}$

$( { \:\frac{1}{2} + \frac{1}{4} + \frac{1}{3}})^{ - 1}$

${( \frac{6 + 3 + 4}{12} })^{ - 1}$

${ (\frac{13}{12} )}^{ - 1}$

$\frac{12}{13}$

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