Question

simplify :
$( {a}^{2} \: + a \: + 1) \: + 5a \: \\ and \: find \: its \: value \: for \: \\ 1. a = 1 \\ 2. a \: = - 1$
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Answer 1

Answer:

» (a² + a + 1) + 5a

= a² + 6a + 1

1. For a = 1, we get

» a² + 6a + 1 = 8

2. For a = -1, we get,

» a² + 6a + 1 = - 4