Question

Simplify
$a( {a}^{2} + a + 1) + 5 \: and \: find \: its \: value \: for \\ 1) \: a = 1$
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Answer 1

$\sf{}a( {a}^{2} + a + 1) + 5 \: and \: find \: its \: value \: for \\ 1) \: a = 1$

$\sf{}{a}^{3} + {a}^{2} + 1+5$

insert Value of a

$\sf{}= {1}^{3} + {1}^{2} + 1+5$

$\sf{}= 1 + 1 + 1+5$

$=\pink{\star\boxed{\sf{}8}\star}$

hope it helps!

Answer 2

$\huge \bold{ \green{ \underline{ \red{\boxed{ \blue{ \cal{ANSWER : - }}}}}}}$

Substituting the value of a=1 in the expression:

$a( {a}^{2} + a + 1) + 5$

$= 1( {1}^{2} + 1 + 1) + 5$

$= 1(1 + 1 + 1) + 5$

$= (1 \times 3 )+ 5$

$= 3 + 5$

$= \huge 8 \: answer$

$\large \blue{ \boxed{ \red{hope \: it \: helps.....}}}$