Question

Simplify:
$( \frac{1}{3})^{ - 2} + ( \frac{1}{4} ) ^{ - 2} + ( \frac{1}{5} ) ^{ - 2} - ( \frac{1}{6} ) ^{ - 2}$
​

Answer 1

$\huge{\underline\mathfrak{\blue{Solution}}}$

Step-by-step explanation:

${\small{\mathtt{(\frac{1}{3})^{-2}+(\frac{1}{4})^{-2}+(\frac{1}{5})^{-2}-(\frac{1}{6})^{-2}}}}</p><p>$

• Using identity (a/b)^{-m} = (b/a)^{m}

${\small{\implies{\mathtt{3^{2}+4^{2}+5^{2}-6^{2}}}}}$

${\small{\implies{\mathtt{9+16+25-36}}}}$

${\small{\implies{\boxed{\mathtt{\pink{14}}}}}}$