Math, asked by gharatanil30, 4 months ago

simplify the above question​

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Answered by shreekrishna35pdv8u8
0

Answer:

 \frac{ {x}^{2} + 5x + 6 }{ {x}^{2}  + 7x + 10 }  \times  \frac{ {x}^{2} + 9x + 20 }{ {x}^{2}  + 7x + 12}  \\  =  \frac{{x}^{2} + 2x  + 3x+ 6}{{x}^{2}  + 2x + 5x + 10}  \times  \frac{{x}^{2} + 4x + 5x + 20 }{{x}^{2}  + 3x + 4x + 12}  \\  =  \frac{ {x}(x + 2) + 3(x + 2) }{x(x + 2) + 5(x + 2)}  \times  \frac{x(x + 4) + 5(x + 4)}{x(x + 3) + 4(x + 3)}  \\  =  \frac{(x + 2)(x  + 3)}{(x + 2)(x + 5)}  \times \frac{(x + 4)(x + 5)}{(x + 3)(x + 4)} \\  = 1

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