Question

Simplify the expreresion
a²+2a²(b²-4) -a²b²-b²
and find its value when a =5
b=-5
​

Answer 1

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

=>a²+2a²(b²-4)-a²b²-b²

[a²-b²=(a+b)(a-b)]

=>a²+2a²(b²-2²)-a²b²-b²

=>a²+2a²[(b+2)(b-2)]-a²b²-b²

=>a²+2a²(b+2)(b-2)-a²b²-b²

When a=5 & b=-5

=>(5)²+2(5)²(-5+2)(-5-2)-(5)²(-5)²-(-5)²

=>25+50(-3)(-7)-625-25

=>25+1050-650

=>1075-650

=>425

If we solve through this :

=>25+50(-3)(-7)-625-25

=>25+1050-600

=>1075-600

=>475

Answer 2

Answer:

$\huge\rm\purple{AnsweR}$

a² + 2a² (b²-4) - a²b² - b²

➡️ a² + 2a²b² - 7a² - a²b² - b²

➡️ a² - 7a² + 2a²b² - a²b² - b²

➡️ -6a² + a²b² - b²

Put the value of a = 5 , b = -5 in the expression.

-6×(5)² + (5)²(-5)² - (-5)²

➡️ -6 × 25 + 25 × 25 - 25

➡️ -150 + 625 - 25

➡️ -150 + 600

➡️ 450