Simplify the expression using the distributive property.
2(-3p + 7) + 3(p -5)
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Step-by-step explanation:
(3p2 + q2) (2p2 – 3q2) Suppose (a + b) and (c – d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below.
(a + b) × (c – d) = a × (c – d) + b × (c – d)
= (a × c – a × d) + (b × c – b × d) = ac – ad + bc – bd Let, a= 3p2, b
= q2, c= 2p2, d= 3q2
Now, = 3p2× (2p2 – 3q2) + q2 × (2p2 – 3q2) = [(3p2× 2p2) + (3p2× -3q2)] + [(q2 × 2p2) + (q2 × -3q2)]
= [6p4 – 9p2q2 + 2q2p2 – 3q4)]
= [6p4 – 7p2q2 – 3q4]
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