Question

Simplify the following::

(1/9)^-2-3×27^2/3 × 9^0+(9/81)^-1/2


Please solve this
It's very urjent
Please...❤​

Answer 1

Answer:

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(sneha )

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Answer 2

Solution :-

Some basics before solving :-

$\star x^n = (x)(x)(x) ....[n\: times]$

$\star x^0 = 1$

$\star x^m \times x^n = x^{(m + n)}$

$\star x^m \div x^n = x^{(m - n)}$

$\star x^{\frac{1}{a}} = \sqrt[a]{x}$

$\star x^{-m} = \dfrac{1}{x^m}$

Now solving :-

$\left(\dfrac{1}{9}\right)^{-2} - 3 \times 27^{\frac{2}{3}} \times 9^0 + \left(\dfrac{9}{81}\right)^{\frac{-1}{2}}$

$= \left(9\right)^{2} - 3 \times (3^3)^{\frac{2}{3}} \times 9^0 + \left(\dfrac{81}{9}\right)^{\frac{1}{2}}$

$= \left(9\right)^{2} - 3 \times (3)^{\frac{6}{3}} \times 9^0 +\left(\frac{9}{1}\right)^{\frac{1}{2}}$

$= \left(9\right)^{2} - 3 \times (3)^{2} \times 9^0 + \left(9\right)^{\frac{1}{2}}$

$= 81 - 3\times 9 \times 1 + 3$

$= 84 - 27$

$= 57$