Question

Simplify the following ​

Answer 1

(2a+3b)^3= (2a)3+(3b)3+3(2a)(3b)(2a+3b)

Using, (a+b)^3=a^3+b^3+3ab(a+b)

=8a^3+27b^3+18ab(2a+3b)

=8a^3+27b^3+36a^2b+54ab^2 .........(i)

(2a−3b)^3=(2a)^3−(3b)^3−3(2a)(3b)(2a−3b)

Using, (a−b)^3=a^3−b^3−3ab(a−b)

=8a^3−27b^3−18ab(2a−3b)

=8a^3−27b^3−36a^2b+54ab^2......(ii)

adding (i) from (ii) we get,

(2a+3b)^3+(2a−3b)^3 =

= 8a^3+27b^3+36a^2b+54ab^2+(8a^3−27b^3−36a^2b+54ab^2)

= 8a^3+ 8a^3+27b^3-27b^3+36a^2b-36a^2b+54ab^2+54ab^2

= 8a^3+ 8a^3+54ab^2+54ab^2

= 16a^3+108ab^2

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Answer 2

Answer:

16a²+27ab² is your answer

hope it helps you