Math, asked by prernasingh20168, 2 months ago

simplify the following​

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Answered by 12thpáìn
222

Simplify

(i)

 {\implies  \sf\sqrt{50  }  -  \sqrt{98}  +  \sqrt{162} }

{\implies\sf\sqrt{2 \times  {5}^{2}   }  -  \sqrt{2 \times  {7}^{2} }  +  \sqrt{2 \times  {3}^{4} }}

{\implies\sf\sqrt{  {5}^{2}  \times 2  }  -  \sqrt{ {7}^{2} \times 2 }  +     \sqrt{ {3}^{4}  \times 2}}

{\implies{\sf\sqrt{  {5}^{2}    }  \times   \sqrt{2}  -  \sqrt{ {7}^{2}  } \times   \sqrt{2}  +     \sqrt{ {3}^{4}  }  \times  \sqrt{2} }}

{\implies{\sf {5}^{ \frac{2}{2}    }  \times   \sqrt{2}  -   {7}^{ \frac{2}{2}   } \times   \sqrt{2}  +      {3}^{ \frac{2}{2}   }  \times  \sqrt{2} }}

{\implies{ \sf{5}\times   \sqrt{2}  -   {7} \times   \sqrt{2}  +      { {3}^{2} }   \times  \sqrt{2}} }

{\implies{ \sf{5}\times   \sqrt{2}  -   {7} \times   \sqrt{2}  +      { 9 }   \times  \sqrt{2} }}

{{\implies\sf {5} \sqrt{2}  -   {7}    \sqrt{2}  +      { 9 }    \sqrt{2}} }

{\implies{\sf {14} \sqrt{2}  -   {7}    \sqrt{2}} }

\implies{ \bf{ \pink{ {7}    \sqrt{2} }}}

(ii)

 {\implies\sf {2 \sqrt{50}  \times 3 \sqrt{32} \times 4 \sqrt{18}  }}

{{\implies\sf2 \sqrt{2 \times  {5}^{2} }  \times 3 \sqrt{ {2}^{5} } \times 4 \sqrt{2 \times  {3}^{2} }  }}

{\implies{\sf2(5 \times  \sqrt{2} ) \times 3(4  \times \sqrt{2})  \times 4 (3 \times  \sqrt{2} )} }

{{\implies\sf2(5 \times  \sqrt{2} ) \times 12 \sqrt{2}   \times 12 \sqrt{2}} }

{\implies{\sf2(5 \times  \sqrt{2} ) \times 144( \sqrt{2} \times  \sqrt{2})  }}

{\implies{\sf2(5 \times  \sqrt{2} ) \times 144 \times 2 } }

{\implies{\sf2(5 \times  \sqrt{2} ) \times 288  }}

{\implies{\sf10 \sqrt{2}  \times 288 } }

{  {\implies \bf{ \pink{2880 \sqrt{2}  }}} }

Hope It Helpful ❣️

Answered by rosoni28
15

\huge\pink{\boxed{\green{\mathfrak{\overbrace{\underbrace{\fcolorbox{red}{aqua}{\underline{\pink{✯Answer✯}}}}}}}}}

(i)

√50-√98-√162

=√25 × √2 - √49 × √2 - √81 × √2

=5√2 - 7√2 - 9√2

-11√2(Ans).

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