Math, asked by aswinbabu911, 3 months ago

Simplify the following and write in exponential form.(3^6 ÷ 3^8) ×3^-4​

Answers

Answered by gangadhar825
0

Answer:

(3

6

÷3

8

)

4

×3

−4

= \Big(\frac{3^{6}}{3^{8}}\Big)^{4} \times \frac{1}{3^{4}}=(

3

8

3

6

)

4

×

3

4

1

= \Big(\frac{1}{3^{8-6}}\Big)^{4} \times \frac{1}{3^{4}}=(

3

8−6

1

)

4

×

3

4

1

\boxed{ \pink{ \frac{a^{m}}{a^{n}} = \frac{1}{a^{n-m}} }}

a

n

a

m

=

a

n−m

1

= \frac{1}{(3^{2})^{4}} \times \frac{1}{3^{4}}=

(3

2

)

4

1

×

3

4

1

= \frac{1}{3^{2\times 4 } \times 3^{4}}=

3

2×4

×3

4

1

= \frac{1}{3^{8+4}}=

3

8+4

1

= \frac{1}{3^{12}}=

3

12

1

Therefore.,

\red{(3^{6} \div 3^{8})^4 \times 3^{-4}}(3

6

÷3

8

)

4

×3

−4

\green { = \frac{1}{3^{12}}}=

3

12

1

Step-by-step explanation:

please mark as brainliest

Similar questions