Question

simplify the following by rationaizing the denominator 7√3-5√2/√48+√18​

Answer 1

Answer:

$\frac{7 \sqrt{3} - 5 \sqrt{2} }{ \sqrt{48} + \sqrt{18} } = \frac{7 \sqrt{3} - 5 \sqrt{2} }{4 \sqrt{3} + 3 \sqrt{2} } = \frac{7 \sqrt{3} - 5 \sqrt{2} }{4 \sqrt{3} + 3 \sqrt{2} } \times \frac{4 \sqrt{3} - 3 \sqrt{2} }{4 \sqrt{3} - 3 \sqrt{2} } =$

$\frac{28 \times 3 - 20 \sqrt{6} - 21 \sqrt{6} + 15 \times 2 }{(4 \sqrt{3}) {}^{2} - (3 \sqrt{2} ) {}^{2} } = \frac{84 - 41 \sqrt{6} + 30}{48 - 18} = \frac{114 - 41 \sqrt{6} }{30}$

Ans.