Question

Simplify the following by Rationalising the denominator : $\frac{1}{\sqrt{7}-\sqrt{6}}$

Answer 1

$\bf\underbrace{ANSWER}$

$\sqrt{7}+\sqrt{6}$

$\bf\underbrace{STEP \ BY \ STEP \ EXPLANATION}$

$We \ have,$

$\frac{1}{\sqrt{7}-\sqrt{6}}=\frac{1}{\sqrt{7}-\sqrt{6}}×\frac{\sqrt{7}+\sqrt{6}}{\sqrt{7}+\sqrt{6}}$

$(Multiply \ and \ divide \ by \ \sqrt{7}+\sqrt{6})$

$\frac{\sqrt{7}+\sqrt{6}}{(\sqrt{7}-\sqrt{6}) (\sqrt{7}+\sqrt{6})}=\frac{\sqrt{7}+\sqrt{6}}{(\sqrt{7})^{2}-(\sqrt{6})^{2}}$

-$\frac{\sqrt{7}+\sqrt{6}}{7-6}=\sqrt{7}+\sqrt{6}$

___________________________

Answer 2

Answer:

above answer is right

Step-by-step explanation:

please follow me and mark brainliest