Math, asked by sujithkumar1122, 7 months ago

Simplify the following by Rationalising the denominator : \frac{1}{\sqrt{7}-\sqrt{6}}

Answers

Answered by EnchantedBoy
5

\bf\underbrace{ANSWER}

\sqrt{7}+\sqrt{6}

\bf\underbrace{STEP \ BY \ STEP \ EXPLANATION}

We \ have,

\frac{1}{\sqrt{7}-\sqrt{6}}=\frac{1}{\sqrt{7}-\sqrt{6}}×\frac{\sqrt{7}+\sqrt{6}}{\sqrt{7}+\sqrt{6}}

(Multiply \ and \ divide \ by \ \sqrt{7}+\sqrt{6})

\frac{\sqrt{7}+\sqrt{6}}{(\sqrt{7}-\sqrt{6}) (\sqrt{7}+\sqrt{6})}=\frac{\sqrt{7}+\sqrt{6}}{(\sqrt{7})^{2}-(\sqrt{6})^{2}}

-\frac{\sqrt{7}+\sqrt{6}}{7-6}=\sqrt{7}+\sqrt{6}

___________________________

Answered by BrainlyBoy60022
0

Answer:

above answer is right

Step-by-step explanation:

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