Question

SIMPLIFY THE FOLLOWING:-

c²-d²/c²-2cd+d² × cd+d²/1​

Answer 1

Answer:

c²-d²/c²-2cd+d² × cd+d²/1

$\frac {(c-d)(c+d)}{ (c-d)^2} × \frac {cd+d^2}{1}$

$\frac {(c+d)}{ (c-d)} × d\frac{(c+d)}{1}$

$\frac { {(c+d)}×{(c+d)} × d} {c-d}$

$\frac { {(c+d)}×{(c+d)} × d} {c-d}$

$\frac { {(c+d)^2} × d} {c-d}$

$\frac { {(c+d)^2}(c-d) × d} {(c-d)^2}$

$\frac { {(c+d)^2}(cd-d^2) } {(c-d)^2}$

$\frac { {(c^2+d^2+2cd)}(cd-d^2) } {c^2+d^2-2cd}$

Answer 2

$\frac {(c²-d²)}{ c² -2cd+d² } × \frac {cd+d^2}{1}\\\\\frac {(c-d)(c+d)}{ (c-d)^2} × \frac {cd+d^2}{1} \\\\ \frac {(c+d)}{ (c-d)} × d\frac{(c+d)}{1} \\\\\frac { {(c+d)}×{(c+d)} × d} {c-d} \\\\\frac { {(c+d)}×{(c+d)} × d} {c-d} \\\\\frac { {(c+d)^2} × d} {c-d} \\\\\frac { {(c+d)^2}(c-d) × d} {(c-d)^2} \\\\\frac { {(c+d)^2}(cd-d^2) } {(c-d)^2}\\\\\frac { {(c^2+d^2+2cd)}(cd-d^2) } {c^2+d^2-2cd}$