simplify the following expression (x+y+z)²(x+y-z)²
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hey mate
(x+y+z)² it seems to be an identity
so applying the suitable identity to the question
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
(x+y+z)²=x²+y²+z²+2(xy+yz+zx)
while in ,
{x+y+( - z) }²=x²+y²-z²+2(xy-yz-zx)
and firther on multiply both if you want.....
hope it will help you....✌
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