Simplify the following expressions and find the value for x=1 y=1 z=2 (x³+y³-z³)(2x+y-z) answer is 24
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Answer:
x+y+z=4 and x
2
+y
2
+z
2
=50
We know,
(a+b+c)
2
=(a
2
+b
2
+c
2
)+2(ab+bc+ca)
Here,
a=x,b=y,c=−z
Thus,
(x+y−z)
2
=x
2
+y
2
+z
2
+2(xy−yz−xz)
=>4
2
=50+2(xy−yz−xz)
=>
2
16−50
=(xy−yz−xz)
=>(xy−yz−xz)=−17
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