Question

Simplify the following. i) (8 ^2 + 3x- 1) + (4x+ 6- 7^ 2 ) ii) (5p+ 7q) – (3p- 4q) + (-2p+ 5q)

I need help fast​

Answer 1

$\circ \: \: \: {\tt{ (8^2 + 3x - 1)+(4x+6-7^2) = 20 - 7x }}$

$\circ \: \: \: {\tt{ (5p+ 7q) – (3p - 4q) + (-2p+ 5q) = 16q }}$

Explanation

Question 1:

$\colon\implies{\tt{ (8^2 + 3x - 1)+(4x+6-7^2) }} \\ \\ \\ \colon\implies{\tt{ (64 + 3x - 1) + (4x + 6 - 49) }} \\ \\ \\ \colon\implies{\tt{ (64 + 3x - 1 + 4x + 6 - 49) }} \\ \\ \\ \colon\implies{\tt{ 70-50 + 3x + 4x }} \\ \\ \\ \colon\implies{\tt\red{ 20 - 7x }}$

Question 2:

$\colon\implies{\tt{ (5p+ 7q) – (3p - 4q) + (-2p+ 5q) }} \\ \\ \\ \colon\implies{\tt{ 5p + 7q - 3p + 4q - 2p + 5q }} \\ \\ \\ \colon\implies{\tt{ \cancel{5p } - \cancel{5q} + 16q }} \\ \\ \\ \colon\implies{\tt\red{ 16q }}$