Question

Simplify the following into their lowest forms.

Answer 1

Solution:-

given by:-
$\frac{ {x}^{3} + ( {2}^{3} )}{ {x}^{4} + 4 {x}^{2} + 16 } \\ \frac{(x + 2)( {x}^{2} + 4 - 2x) }{ {x}^{4} + 8 {x}^{2} + {4}^{2} - 4 {x}^{2} } \\ \frac{(x + 2)( {x}^{2} + 4 - 2x) }{ {( {x}^{2} + {2}^{2}) }^{2} - {(2x)}^{2} } \\ \frac{(x + 2)( {x}^{2} + 4 - 2x) }{( {x}^{2} + 4 - 2x)( {x}^{2} + 4 + 2x) } \\ \frac{(x + 2)}{ ({x}^{2} + 2x + 4) } ans$
☆i hope its help☆

Answer 2

HELLO DEAR,
$\mathbf{\frac{ {x}^{3} + ( {2}^{3} )}{ {x}^{4} + 4 {x}^{2} + 16 } } \\ \\ \mathbf{\frac{(x + 2)( {x}^{2} + 4 - 2x) }{ {x}^{4} + 8 {x}^{2} + {4}^{2} - 4 {x}^{2} }} \\ \\ \mathbf{ \frac{(x + 2)( {x}^{2} + 4 - 2x) }{ {( {x}^{2} + {2}^{2}) }^{2} - {(2x)}^{2} }} \\ \\ \mathbf{ \frac{(x + 2)( {x}^{2} + 4 - 2x) }{( {x}^{2} + 4 - 2x)( {x}^{2} + 4 + 2x) }} \\ \\ \mathbf{ \frac{(x + 2)}{ ({x}^{2} + 2x + 4) } }$


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